[1+(-1\2)]+[1\2+(-1\3)]+[1\3+(-1\4)]+......[1\1999+(-1\2000)]
来源:百度知道 编辑:UC知道 时间:2024/05/16 18:23:04
ji suan ti
=?
=?
原式=1-1/2+1/2-1/3+1/3-1/4……1/1999-1/2000(抵消)
=1-(1/2000)
=1999/2000
[1+(-1\2)]+[1\2+(-1\3)]+[1\3+(-1\4)]+......[1\1999+(-1\2000)]=
1+[(-1\2)+1\2]+[(-1\3)+1\3]+(-1\4)+......1\1999+(-1\2000)=
1-1\2000=1999\2000
太复杂了
看见数字头就大
(1-1\2004)(1-1\2003)(1-1\2002).........(1-1\3)(1-1\2)
(1+1\2)*(1+1\3)*(1+1\3)*(1+1\4)*......(1+1\20)
(1\2+1\3+...+1\2006)(1+1\2+1\3+...+1\2005)-(1+1\2+1\3+...+1\2006)(1\2+1\3+...+1\2005)
((1+1\2)(1+1\3)(1+1\4)(1+1\5)------(1+1\100))\(1-1\2)(1-1\3)(1-1\4)------(1-1\100)
((1+1\2)(1+1\3)(1+1\4)(1+1\5)------(1+1\100))\(1-1\2)(1-1\3)(1-1\4)------(1-1\100)等多少
1\2+1\4+1\8+...+1\256+1\512+1\1024=??
(1-1\2)+(1\2-1\3)+(1\3-1\4)+(1\4-1\5)+(1\5-1\6)+........(1\2005-1\2006
(1-1\2)+(1\2-1\3)+(1\3-1\4)+(1\4-1\5)+(1\5-1\6)+........(1\2005-1\20把括号变为绝对号咋么做06
[1+(-1\2)]+[1\2+(-1\3)]+[1\3+(-1\4)]+......[1\1999+(-1\2000)]
1+1\2+1\4+……